The width of a rectangle is 7 inches less than its length. the area of the rectangle is 120 square inches. solve for the dimensions of the rectangle.

length: a0 inches

width: inches

Length is 15 inches

Width is 8 inches

Step-by-step explanation:

A = L*W

the Width = L-7

120 = L (L-7)

120 = L^2-7L

subtract 120 from each side

0 = L^2 - 7L - 120

(L-15) (L +8 )

so L = 15  inches

and W = 15-7 = 8 inches

check your does 15*8 = 120? yes!

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)