If triangle pqr is an equilateral triangle, solve x and y.

pq is 14y-59
qr is 9y+1
rp is 11y-23
angle r is 7x-3

20 points

x = 9 and y = 15

Step-by-step explanation:

An  equilateral triangle, all sides and angles are congruent and each angle is equal 60 degrees

PQR is an equilateral triangle

So

PQ = QR = RP

Given:

PQ is 14y-59

QR is 9y+1

RP is 11y-23

Angle R is 7x-3

PQ = QR

Plug in

14y-59  = 9y+1

5y = 60

 y = 15

Angle R is 7x-3, also <R = 60

So

7x - 3 = 60

7x = 63

 x = 9

Answer

x = 9 and y = 15

x= 9 and y= 12

Step-by-step explanation:

Given : Triangle PQR is an equilateral triangle.

PQ is 14y-59

QR is 9y+1

RP is 11y-23

Angle R is 7x-3                 (1)

We know that , In an equilateral triangle

All sides are equal.

⇒ PQ = QR

⇒  14y-59 = 9y+1

⇒ 14y-9y =1+59  [Subtract 9y and add 59 on both sides]

⇒ 5y=60

⇒ y= 12    [Divide both sides by 5]

All angle angles of equilateral triangle are equal and have measure 60° .

⇒ Angle R =  60°

⇒  7x-3=  60      [From (1)]

⇒ 7x= 63  [Add 3 on both sides]

⇒ x= 9  [Divide both sides by 7]

Hence, the value of x= 9 and y= 12.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

it shoild be o

step-by-step explanation: