Parallelogram defg is transformed to parallelogram vstu.

which statement about the transformation is true?
parallelogram defg is the pre-image because it is not the result of the transformation.
parallelogram defg is the image because it is the result of the transformation.
parallelogram vstu is the pre-image because it is the result of the transformation.
parallelogram vstu is the image because it is not the result of the transformation.

A, because a pre-image means an image before its altered, and VSTU would be the image as a result of DEFG being transformed

Parallelogram DEFG is the pre-image because it is not the result of the transformation.

Step-by-step explanation:

Parallelogram DEFG is transformed to parallelogram VSTU.

Though any image is not given, but this is a simple question based on definition, so we can solve it.

DFEG is the original parallelogram or pre image that is transformed to make VSTU, as it is given DEFG is transformed to VSTU.

So, the true statement about the transformation is -

Parallelogram DEFG is the pre-image because it is not the result of the transformation.

35 is an outlier

step-by-step explanation:

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )