At an amusement park, the probability that a child eats a hot dog and drinks a soda pop is 0.47. the probability that a child eats a hot dog is 0.69 and the probability that a child drinks soda pop is 0.86. what is the probability (rounded to the nearest hundredth) that a child drinks soda pop given that the child has already eaten a hot dog?

hint: p(a|b)=p(a∩b) / p(b)

0.55

0.40

0.32

0.68

option D

0.68

Step-by-step explanation:

Conditional Probability:

Finding the probability of an event given that something else has already happened.

p(A) =  The probability that a child eats a hot dog  = 0.69

p(B) =  The probability that a child drinks soda pop = 0.86

p(A∩B) = The probability that a child eats a hot dog and drinks a soda pop = 0.47

Formula to use

P(A|B) = P(A∩B) / P(A)

          = 0.47 / 0.69

          = 0.68

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

10 you would take 50/ .2

step-by-step explanation: