One year, a group of doctors held a fundraiser and sent $35,885 to a clinic in need of support. each year after that, the doctors sent another $2500

after how many years will the total amount sent by the doctors first exceed $250,000?

86 years after the $35,885 donation is made

Step-by-step explanation:

Let n be the total number of years.

Each year they sent $2500, so in n year they send 2500n dollars.

They sent $35,885 to start with, so after n years, they will have sent a total of

2500n + 35,885

We need to find the value of n for which 2500n + 35,885 exceeds $250,000.

2500n + 35,885 > 250,000

2500n > 214,115

n > 214,115/2500

n > 85.6

The first year after 85.6 years have passed is year 86.

c

step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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