Arose garden is formed by joining a rectangle and a semicircle, as shown below. the rectangle is 31 ft long and 20 ft wide. if the gardener wants to build a fence around the garden, how many feet of fence are required?
(use the value for 3.14 , and do not round your answer. be sure to include the correct unit in your answer.)

133 ft

Given in the question,

length of the rectangle = 31 ft

width of the rectangle= 20 ft

diameter of semicircle = 20 ft

radius of semicircle = 20/2 ft = 10 ft

perimeter of rectangle + perimeter of semicircle

perimeter of rectangle = 2(l+w)

perimeter of semicircle = 1/2(2πr)

2(31 + 20) + 3.14(10)

133.4 ft

≈ 133 ft

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

i cant answer this, theres no table. sorry man

step-by-step explanation: