Find the area of a regular hexagon with a radius of 8 and an apothem of 4 squareroot 3. round your answer to the nearest tenth.

The area of the regular hexagon is 166.3 units^{2}  

Step-by-step explanation:

we know that

The area of a regular hexagon is equal to the area of six equilateral triangles

so

The area of a regular hexagon is

A=6[(1/2)bh]

The length side of the regular hexagon is equal to the radius

b=8 units

h=4\sqrt{3}  units > the apothem

substitute the values

A=6[(1/2)(8)(4\sqrt{3})]=166.3 units^{2}  

my answer is$ 12

step-by-step explanation:

because 15 -2=12

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.