Which of the following polynomials has solutions that are not real numbers?
a)x^2-6x+3
b)x^2+4x+3
c)-x^2-9x-10
d)x^2+2x+3

D) .

Step-by-step explanation:

All four polynomials are quadratic, meaning that the highest power of the unknown in the equation is two.

The sign of the quadratic discriminant, , is a way to tell if a quadratic polynomial comes with non-real solutions.

There are three cases:

How to find the quadratic discriminant?

If the equation is in this form:

,

where a, b, and c are real numbers (a.k.a. "constants.")

Quadratic discriminant:

.

Polynomial in A:

.

.

. There will be no non-real solutions and two distinct real solutions.

Try the steps above for the polynomial in B, C, and D.

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1