Mathematics, 15.10.2019 06:00 clonetrooper099

Let line l be given by the equation ax + by = c.

a. write the equation, in slope intercept form, of the line passing through the point (2, 7) and parallel to line l.

b. write the equation, in slope intercept form, of the line passing through the point (2, 7) and perpendicular to line l.

Answers: 2

Show answers

Answers

Answer from: kajjumiaialome

Part A) $y=-\frac{A}{B}x+\frac{7B+2A}{B}$

Part B) $y=\frac{B}{A}x+\frac{7A-2B}{A}$

Step-by-step explanation:

we have the equation of the line L in standard form

Ax+By=C

isolate the variable y

By=-Ax+C

y=-(A/B)x+C/B

The slope of the line L is equal to

m=-A/B

Part A) Write the equation, in slope intercept form, of the line passing through the point (2, 7) and parallel to line L

Remember that

If two line are parallel, then their slopes are equal

The equation of the line in slope intercept form is equal to

y=mx+b

we have

m=-A/B

point (2,7)

substitute the values and solve for b

7=(-A/B)(2)+b

b=7+2A/B=(7B+2A)/B

The equation of the line is

$y=-\frac{A}{B}x+\frac{7B+2A}{B}$

Part B) Write the equation, in slope intercept form, of the line passing through the point (2, 7) and perpendicular to line L

Remember that

If two line are perpendicular, then the product of their slopes is equal to -1

m1*m2=-1

The equation of the line in slope intercept form is equal to

y=mx+b

we have

m1=-A/B

Find the value of m2

(-A/B)*m2=-1

m2=B/A

point (2,7)

substitute the values and solve for b

7=(B/A)(2)+b

b=7-2B/A=(7A-2B)/A

The equation of the line is

$y=\frac{B}{A}x+\frac{7A-2B}{A}$

Answer from: Quest

answer:

\boxed {\frac{1}{5}}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

solution-

60 * \frac{1}{5} = 12

90 * \frac{1}{5} = 18

75 * \frac{1}{5} = 15

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

hence, the answer would be \boxed {\frac{1}{5}}

What is the scale factor of axyz to auvw?

Answer from: Quest

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

Another question on Mathematics

Mathematics, 21.06.2019 17:30

When the solutions to each of the two equations below are graphed in the xy-coordinate plane, the graphs of the solutions intersect at two places. write the y-cordninates of the points of intersection in the boxes below in order from smallest to largest. y=2x y=x^2-3

Answers: 1

Answer

Mathematics, 22.06.2019 00:30

20 ! brainliest ! add and simplify your answer.

Answers: 1

Answer

Mathematics, 22.06.2019 01:00

Find the rate of change for the situation.you run 7 miles in one hour and 21 miles in three hours.

Answers: 1

Answer

Mathematics, 22.06.2019 02:20

Use the second shift theorem to find the inverse laplace transform of (e^−3s) / (s^2 + 2s − 3)