Aright cylinder has a radius of r inches and height of 2r inches.
in terms of r, the lateral area of the cylinder is r2π square inches.
the area of the two bases together is r2π square inches.
the total surface area of the cylinder is r2π square inches.

Part a) The lateral area is

Part b) The area of the two bases together is

Part c) The surface area is

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

where

LA is the lateral area

B is the area of the base of cylinder

we have

Part a) Find the lateral area

The lateral area is equal to

substitute the values

Part b) Find the area of the two bases together

The area of the  base B is equal to

so

the area of the two bases together is

Part c) Find the surface area of the cylinder

we have

substitute

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

the answer is b.

step-by-step explanation: