What is the sum of an infinite geometric series if 2=5 and r=1/3

Step-by-step explanation:

The problem has a mistake, it should NOT be 2 = 5, rather a=5.

Now, given a = 5 (the first term is a), and

r = 1/3 (common ratio),

we can solve for the sum of the infinite series by using the formula:

Where is the sum of the infinite geometric series,

a is the first term (given as 5), and

r is the common ratio ( r= 1/3 given)

We now plug these into the formula and get our

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.