What is the probability of rolling a number less than 3, and then rolling a prime number? 1/3 1/2 1/36 1/6

Hello, I'll try to make this as easy to understand as possible, anyways, let's begin:

First off, we know there are 6 numbers in a die, so if we want to get a number less than 3, it has the probability of 2/6, which is the same as 1/3.

Then, the prime numbers on a die are 2, 3 and 5, which gives us a probability of 3/6, or 1/2.

Then, we multiply both fractions, like so:

That means the answer is 1/6.

Hope this helped! c:

hi there!

the answer will be d: 2

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560