Question is attached below leave answers as percentages

1) 46%

2) 0.07

3) 0.1148

4) 0.1372

Step-by-step explanation:

Total number of patients = 50

Total number of dogs = 7 + 4 + 5 + 5 + 2 = 23

Part 1)

The percentage of patients that were dogs =

Thus, 46% of the patients were dogs.

So,

p =46% = 0.46

Part 2)

p = 0.46

n = 50

Using the values in the given formula, we get:

Thus, the standard error is 0.07

Part 3)

Z-value for 90% confidence interval is 1.64. This value is found using z-table or can be found using online calculators.

Margin of error = z-value x S.E

Using the values, we can write:

Margin of error = 1.64 x 0.07

Margin of error  = 0.1148

Thus margin of error for 90% confidence interval is 0.1148

Part 4)

Z-value for 95% confidence interval is 1.96

Margin of error = z-value x S.E

Using the values, we can write:

Margin of error = 1.96 x 0.07

Margin of error= 0.1372

Thus margin of error for 95% confidence interval is 0.1372

ian gone lie this got me confused

step-by-step explanation:

the correct answer is x/3+10≥32

hope this !