How many zero pairs must be added to the function
f(x) = x2 – 6x + 1 in order to begin writing the function in vertex form?

There is only one zero pair added i.e. 9.                                          

Step-by-step explanation:

Given : Function

To find : How many zero pairs must be added to the function  in order to begin writing the function in vertex form?  

Solution :

Converting the given function into vertex form,

Adding and subtracting square of 3,

Square form as

So, The required vertex form is

There is only one zero pair added i.e. 9.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1