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Mathematics, 28.10.2019 12:31 pronces

En un triangulo rectangulo abc (b=90) reduce:

j=(sec2c-cot2a) (sen2c+sen2a) es para hoy porf

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En un triangulo rectangulo abc (b=90) reduce:

j=(sec2c-cot2a) (sen2c+sen2a) es para hoy...
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