10 points & brainliest - what are the coordinates of vertex j of the pre-image?

ANSWER

(0,-4)

EXPLANATION

The coordinates of J' are (0,-2).

Let the coordinates of J be (a,b).

Then we apply the rule of the dilation to get,

.

This implies that,

And also,

Hence the vertex J of the preimage is

(0,-4)

The first choice is correct.

(0, -4)

Step-by-step explanation:

A dilation rule of means that the coordinates of each point in the pre-image must be divided by 2.

So, we must multiply the coordinates of each point in the image by 2 to get back to the pre-image.

The coordinates of vertex J' are (0, -2), so those of J must have been (0, -4).

Vertex J moved to the origin along the ray until its coordinates were halved.

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1