Aregular octagon has an apothem measuring 10 in. and a perimeter of 66.3 in. what is the area of the octagon, rounded to the nearest square inch? 88 in.2 175 in.2 332 in.2 700 in.2

Step-by-step explanation:

The area of a regular polygon is calculated using the formula;

where is the apothem and p is the perimeter.

It was given that, the apothem is, and the perimeter is

We substitute into the formula to obtain;

To the nearest square inch, we have;

The answer is:

From the statement we know that the octagon has a apothem of 10in and a perimeter of 66.3in, and we are asked to find the area of the octagon.

We can use the following formula:

Substituting the given information into the area formula, we have:

Rounding to the nearest number we have that:

331.5 ≈ 332

So, the area of the octagon is:

Have a nice day!

idk

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°