Will give

caden rolls two fair number cubes numbered from 1 to 6. he first defines the sample space, as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

based on the sample space, what is the probability of getting a total of 6?

5/36
6/36
7/36
8/36

Given the circumstances, only the rolls (1,5) (2,4) (3,3) (4,2) and (5,1) will give a total of 6, which is 5 possibilities. There is a total of 36 possibilities. This means that the probability of getting a total of 6 is

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.