Solve for x, y, and z
(system of equations with 3 equations)

2x−3y+4z=8, 3x+4y−5z=−4, 4x−5y+6z=12


x = y = z = __

The solution is x=1,y=2,z=3

Step-by-step explanation:

The given system of equations is ;\

2x−3y+4z=8...(1)

3x+4y−5z=−4...(2)

4x−5y+6z=12...(3)

Make x the subject in equation (1)

Put equation (4) into equation (2) and (3)

Multiply through by;

Expand;

Simplify;

Equation (4) in (3)

Put equation (6) into equation (5)

z=3

Put z=3 into equation (6)

y=2(3)-4=2

Put y=2 and z=3 into equation 4

The solution is x=1,y=2,z=3

your answer is the frist one

hop i

step-by-step explanation:

4  

25

5258y

54.

t5

5r

54

5856

542

5458

86

.8558.65

565

565

55898

786

8/95

5896

8656265

556478