We are standing on the top of a 1200 feet tall building and launch a small object upward. the object's vertical position, measured in feet, after t seconds is h(t)=−16t2+160t+1200. what is the highest point that the object reaches?

h = 1600 feet

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The projectile formula is

h(t) = a*t^2 + v*t + h0

Where,

v = initial vertical velocity of the object in feet per second

h0 = initial height of the object in feet

h(t) = −16t^2 +160t + 1200

If we look at the graph, we can find the point in which the height becomes maximum.

For this problem,

h = 1600 feet ,

at t = 5 seconds

b. 13

step-by-step explanation:

as there are 13 students in bowling class therefore the most reasonable answer is b as only 13 students are in the bowling class.

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.