The slope is 7 and it passes through (8,6)

You want to find the equation for a line that passes through the point (8,6) and has a slope of .

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was . So you can right away fill in the equation for a line somewhat to read:

y=x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(8,6). When x of the line is 8, y of the line must be 6.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (8,6).

So, why not plug in for x the number 8 and for y the number 6? This will allow us to solve for b for the particular line that passes through the point you gave!.

(8,6). y=mx+b or 6=0 × 8+b, or solving for b: b=6-(0)(8). b=6.

The equation of the line that passes through the point (8,6) with a slope of 0

is

y=+6

english, cause i can’t you

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula