Which function has an asymptote at x=pi/2?

a) y= sec x

b) y= cot x

c) y= csc x

d) y= cos x

Step-by-step explanation:

Note that y= sec x is the same as y = 1 / cos x, and that cos x is 0 at π/2.  Division by zero is not defined.  Thus, x cannot = π/2, and there is a vertical asymptote there.

Thus, the first answer choice, y = sec x, is the correct one.

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice