Is (0,0) a solution to this system?

The correct answer is option D

No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1

Step-by-step explanation:

It is given two inequalities

y ≥ x² + 2x -4

y > x² + 2x + 1

Check (0, 0) satisfy the inequalities

1).  y ≥ x² + 2x -4

0 ≥ 0² + 2*0 -4

0 ≥  -4

It is true

2). y > x² + 2x + 1

0 > 0² + 2*0 + 1

0  > 1

It is not true

The correct answer is option D

No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1

step-by-step explanation:

where is the questions

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: