What expression equals 4m- 2+(-8m)
a. -2(4m+1)+4m
b. 2(2m-1)-8m
c. none of the above

A &B

Step-by-step explanation:

We need first to remove brackets in our given expression : 4m-2-8m=-4m-2

Check A

Multiply by -2 all member of brackets:

Check B

Multiply by 2 all member of brackets :

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

the answer is: -22 also a

hope i

-lavira: )