Two boxes have the same volume. one box has a base that is 2 inches by 2 inches. the other box has a base that is 4 inches by 4 inches.
how many times as tall is the box with the smaller base?

4 times as tall.

Step-by-step explanation:

Volume of the box with the smaller base = 2*2* h1 = 4h1 where h1 is its height.

Similarly the volume of the larger base box =  4*4 * h2 = 16h2 with height h2.

So the ratio of their volumes is  16h2 / 4h1 = 4h2 / h1.

Now the volumes are equal so 4h2 = h1.

Therefore   h2 = h1/4  so h1 = 4h2.

The box with the smaller base is 4 times as tall as the other box.

4th option is correct xy=-10

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relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4