Law of cosines: a2 = b2 + c2 – 2bccos(a) what is the measure of n to the nearest whole degree? 35° 45° 55° 65° the triangle sides are 7 4 5.74

option C

N ≈ 55°

Step-by-step explanation:

Given in the question a right angle triangle.

To calculate the angle N, we will use following formula

a² = b² + c² -2bcCos(A)

here,

a = 5.74

b = 4

c = 7

A = N°

Plug values in the formula

5.74² = 4² + 7² -2(4)(7)COS(N)

32.95 = 16 + 49 - 56COS(N)

32.95 = 65 - 56COS(N)

32.95 - 65 = - 56COS(N)

-32.05 = - 56COS(N)

minus will cancel out

32.05 =  56COS(N)

COS(N) = 32.05/56

COS(N) = 0.57

N = (0.57)

N = 55.08°

N ≈ 55°

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~