![\sqrt[n]{x^n}=x](/tpl/images/0466/3481/65b9b.png)
![\sqrt[4]{\frac{3}{2x}}](/tpl/images/0466/3481/e044a.png)
. Then:![\frac{\sqrt[4]{3}}{\sqrt[4]{2x}}=\frac{\sqrt[4]{3(2^3x^3)}}{\sqrt[4]{2x(2^3x^3)}}](/tpl/images/0466/3481/b56cf.png)
![\frac{\sqrt[4]{3(8x^3)}}{\sqrt[4]{2x(2^3x^3)}}=\frac{\sqrt[4]{24x^3}}{\sqrt[4]{2^4x^4}}=\frac{\sqrt[4]{24x^3}}{2x}](/tpl/images/0466/3481/5bcc9.png)
Ihave the most trouble with math what’s the answer? ?
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Mathematics, 22.01.2020 22:31 danielacortevpe3i66
Ihave the most trouble with math what’s the answer? ?
Answers: 2
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