Suppose that $12,724 is invested at an interest rate of 6.1% per year, compounded continuously. find the exponential function that describes the amount in the account after time t, in years. what is the balance after 1 year, 2 years, 5 years, 10 years. what is the doubling time

Exponential Function:

Balance after

t=1 $ 13,524.32

t=2 $ 14,374.99

t=5 $ 17,261.69

t=10 $ 23,417.64

Step-by-step explanation:

Formula used to find amount in the account after time t, given the interest rate is compounded continuously

where: P= principal amount or amount invested

r= interest rate

t= time

A= amount after time t

in our question we are given:

P=$12,724

r= 6.1% or 0.061

The above equation is exponential function that describes the amount in the account after time t in years

Now, for t = 1

A= $ 13,524.32

t=2

A= $ 14,374.99

t= 5

A= $ 17,261.69

t=10

A= $ 23,417.64

question is incomplete.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: