What is the amplitude and period of f(t)= -cos 3t?

option c

amplitude 1 ; period 2π/3

Step-by-step explanation:

Given in the question a function,

f(t)=-cos3t

Standard form of cosine function is

f(t)=acos(bt)

Amplitude is given by = |a|

Period of function is given by = 2π/b

So the amplitude is |-1| = 1

    the period is 2π/3 = 2π/3

c. The amplitude is 1.

The period is

Step-by-step explanation:

The given cosine function is ;

This function is of the form;

The amplitude is given by |a|

|-1|=1

The period of this function is given by;

The amplitude is 1.

The period is

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi