Acompany is creating a box without a top from a piece of cardboard, but cutting out square corners with side length x.

which expression can be used to determine the greatest possible volume of the cardboard box?

(15−x)(22−x)x

(x−15)(x−22)x

(15−2x)(22−2x)x

(22x−15)(15x−22)

Volume of box = (15−2x)(22−2x)x

C is correct.

Step-by-step explanation:

A company is creating a box without a top from a piece of cardboard, but cutting out square corners with side length x.

The dimension of the cardboard must be 15 x 22 because all options has same value.

We have rectangle cardboard with 15 x 22. We cut square from each corner of the board with dimension x.

New length of box = 22 - 2x

New Width of box = 15 - 2x

Height of the box = x

Volume of box is equal to volume of cuboid.

Volume of box = LBH

                        = (15-2x)(22-2x)(x)

Hence, The correct volume of the box is (15-2x)(22-2x)(x)

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

-9

step-by-step explanation: