Find the surface area of a cylinder with a height of 42 meters and a diameter that is one third its height.

a. 602 m
b. 686 m
c. 974 m
d. 1568 m

  686π m² . . . . . looks like it is intended to match B

Step-by-step explanation:

The lateral area is the product of the height and circumference:

  LA = (42 m)(1/3·42 m)π = 588π m² ≈ 1847 m²

The base area is the area of the end circles, which is twice the area of one of them. That is ...

  BA = 2·(π/4)(1/3·42 m)² = 98π m² ≈ 309 m²

Then the total surface area is ...

  A= LA + BA = (588π +98π) m² = 686π m² ≈ 2155 m²

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