Solve this equation
-4sin^2x + 16sin^2x/2-1=0

x=(n−12)π or (2n−1π)

Explanation:

-4 sin 2 x−10(sin x−1)(sin+)=sin x−=0 sin x=1 x 1π5π...x,x−,=2,...

we can say that,

x=12π,32π,52π,72π,...

we can use arithmetic progression to solve this sequence where,

a=12π,d=π.Tn=12π+(n−1)π=(12+n−1)πTn=(n−12)π or (2n−1)π2

Therefore it general solution for

x is (n 12π or (n−1)π2 for all n

Hope this helps!!!

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