Para medir la altura de una torre, juan se situa en un punto del suelo horizontal y observa el punto mas alto de la torre bajo un angulo de 62°. se acerca 6 metros a la torre en linea recta y el angulo es de 79° haya la altura de la torre

The height of the tower is 17.79 m

Step-by-step explanation:

The question in English is

To measure the height of a tower, Juan stands at a point on the horizontal ground and observes the highest point of the tower under an angle of 62°. He approaches the tower 6 meters in a straight line and the angle is 79° Find the height of the tower

see the attached figure to better understand the problem  

In the right triangle ABC

tan(62°)=h/x

h=(x)tan(62°) ------> equation A

In the right triangle DBC

tan(79°)=h/(x-6)

h=(x-6)tan(79°) ------> equation B

Equate equation A and equation B and solve for x

(x)tan(62°)=(x-6)tan(79°)

(x)tan(62°)-(x)tan(79°)=-(6)tan(79°)

x=-(6)tan(79°)/[tan(62°)-tan(79°)]

x=9.46 m

Find the value of h

h=(9.46)tan(62°)=17.79 m

which expression represents the approximate length of bc?

step-by-step explanation: