Agarage is scheduled to have a temporary gravel floor until the homeowner has a he funds necessary to poor concrete floor. washed gravel is 105 pounds per cubic foot. f the inside dimension of the garage if the l35’/ w.22’ and 18” deep. how much the gravel will be required for the floor. round the answer to the next whole ton? ok

842 pounds

Step-by-step explanation:

Given in the question,

dimension of the garage is 35'' by 22'' by 18''

Total gravel need to be filled

L x W x H

35'' x 22'' x 18''

13860 in³

1 in³ = 0.000578704 ft³

13860 in³ = 13860 * 0.000578704 ft³

                = 8.0208 ft³

Given that gravel is 105 pounds per cubic foot

so,

105 x 8.0208

842.18793

≈ 842 pounds

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

throw the computer

step-by-step explanation: