The table below lists four names and their corresponding aproximant weights on earth.

mass (kilograms) | weight (newtons)
20 | 196
50 | 490
x | 1078
130 | 1274
140 | 1372
the ratio weight to mass in contant. wich statemen describes the ratio of weight to mass and the value of x in the table?
a. 98/10; x =90
b. 98/10; =110
c. 10/98; x =90
d. 10/98; x= 110

The statement which describes the ratio of weight to mass and the value of x is ⇒ 98/10 ; = 110 answer B

Step-by-step explanation:

* Lets explain how to solve the problem

- The mass (kilograms) values are

  20 , 50 , x , 130 , 140

- The corresponding weight (newtons) values are

  196 , 490 , 1078 , 1274 , 1372

* Lets find the ratio between weight to mass

∵ 196/20 ⇒ divide up and down by 2

∴ 196/20 = 98/10

∵ 490/50 ⇒ divide up and down by 10

∴ 49/5 ⇒ multiply up and down by 2

∴ 49/5 = 98/10

∴ 490/50 = 98/10

∵ 1274/130 ⇒ divide up and down by 13

∴ 1274/130 = 98/10

∵ 1372/140 ⇒ divide up and down by 14

∴ 1372/140 = 98/10

- All the ratios between weight to mass equal 98/10

∴ 1078/x = 98/10 ⇒ by using cross multiplication

∴ 98(x) = 1078(10)

∴ 98 x = 10780 ⇒ divide both sides by 98

∴ x = 110

* The statement which describes the ratio of weight to mass and the

  value of x is 98/10; = 110

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.