What is g’(x)? calculus derivative

12

Step-by-step explanation:

h'(x) = [f(x)*g(x)] '=f'(x )g(x) + f(x)g'(x)

h'(1) = [f(1)*g(1)] '=f '(1)g(1) + f(1)g'(1)

From the table f '(1)= -3,  g(1)=2,   f(1)= 3, g'(1) =6

h'(1) = f '(1)g(1) + f(1)g'(1) = -3*2 + 3*6= - 6+ 18 = 12

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)