Find the axis of symmetry and vertex for the following equations. y=-x^2-4x+1

hello :

the axis of symmetry  is the line wher an equation is : x =2

the vertex is : (  2 ; 5 )

Step-by-step explanation:

write this expression in the vertex form :

y=-x²-4x+1

y = - ((x² +4x +4) -4) +1

y = - (x -2)²+5

the axis of symmetry  is the line wher an equation is : x =2

the vertex is : (  2 ; 5 )

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet