Abox contains 4 white balls and 6 yellow balls a ball is drawn at random light from the box and is not replaced what is the probability that both balls are white

An

1/2

Step-by-step explanation:

There are 10 balls total and two balls are removed and not replaced so your fraction is 4/8 but you need to simplify it to 1/2

2/15

Step-by-step explanation:

p(first white)=4/10=2/5;

P(second white)=3/9=1/3;

P(both white)=2/5 x 1/3=2/15

ou would have 12 of each

(8+64)^2= 5184 < answer

step-by-step explanation:

2^3 = 8

4^3= 64

(8+64)^2 = 5184