![\sqrt [3] {\frac {12x ^ 2} {16y}}](/tpl/images/0503/8032/8f6ff.png)
![\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=](/tpl/images/0503/8032/b89df.png)
![(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=](/tpl/images/0503/8032/11c30.png)
in the denominator:![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=](/tpl/images/0503/8032/2cccb.png)
![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=](/tpl/images/0503/8032/5df56.png)
![\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=](/tpl/images/0503/8032/dbd34.png)
![\frac{\sqrt[3]{6x^2*y^2}}{2y}](/tpl/images/0503/8032/5256e.png)
What is the simplified form of the following expression? assume y=0 ^3 sqrt 12x^2/16y
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Mathematics, 05.02.2020 11:58 derisepicowe0fa
What is the simplified form of the following expression? assume y=0 ^3 sqrt 12x^2/16y
Answers: 1
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