Function 1 has the least minimum value and its coordinates are (2, -7).
Step-by-step explanation:
Two quadratic functions are shown.
Function 1:
![f(x) = 2x^2 - 8x + 1](/tpl/images/0474/5135/1a770.png)
Function 2:
x g(x)
-2 2
-1 -3
0 2
1 17
LEts find the vertex to get the minimum value
to get the minimum value for function 1 we use formula ![x=\frac{-b}{2a}](/tpl/images/0474/5135/ce62e.png)
, a=2, b=-8
![x=\frac{-b}{2a}=\frac{8}{2(2)}=2](/tpl/images/0474/5135/22cd8.png)
when x=2, the value of ![f(2) = 2(2)^2 - 8(2) + 1=-7](/tpl/images/0474/5135/4fcdd.png)
minimum point of function 1 is (2,-7)
For function 2, we find the minimum point using the table
minimum point of function 2 is (-1,-3)
Function 1 has the least minimum -7.
Function 1 has the least minimum value and its coordinates are (2, -7).