What is the coordinates of the vertex of y+10=4(x-1)^2

(1, -10)

Step-by-step explanation:

Only the y can be on the left hand side. The square has been completed so all you need do is transfer the 10 to the right and read the x,y values for the vertex.

I have provided a graph to show you that the vertex and my answer are the same (hopefully).

y + 10 = 4(x - 1)^2          Subtract 10 from both sides.

y + 10-10=4(x -1)^2 -10  Combine

y = 4(x - 1)^2 - 10

Now we need to make the square term = 0

x - 1  = 0                        Add 1 to both sides

x - 1 + 1 = 0 +1               Combine

x = 1                              When x = 1 the square term will equal 0.

The vertex should be (1, - 10)

d. is the correct answer

step-by-step explanation:

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph