You cut square corners from a piece of cardboard that has dimensions 32 cm by 40 cm. you then fold the cardboard to create a box with no lid. to the nearest centimeter, what are the dimensions of the box that will have the greatest volume?

h = 6 cm  

l = (32-2(6)) =  20 cm

w = (40-2(6)) = 28 cm

Step-by-step explanation:

Given in the question a piece of cardboard having dimensions 32 by 40

Suppose we cut square of length x

When you cut square corners from a piece of cardboard, two sides are 32-2x, and other two sides are 40-2x lengths

Formula for the volume of box

v = height * length  * width

v = x  (32-2x)  (40-2x)

v = 4x³ - 144x² + 1280x

Find derivative and equal it to 0

dv/dx = 4(3)x² - (2)144x + 1280

      0 = 12x² - 288x + 1280

x1 = 18.110

x2 =5.88

Select x and plug value of x to find dimension

(32-2x) > 0

2x < 32

 x < 16

so domain say that x should be less than 16 which means x = 5.88 ≈ 6 cm

h = 6 cm  

l = (32-2(6)) =  20 cm

w = (40-2(6)) = 28 cm

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

the answer is 54 sq. ft. i just did this question, on odyssey ware, and it was right. make brainliest.