What is the equation of the line that passes through (-3,-1) and has a slope of 3/5

y+1 = 3/5(x+3)  (point slope form)

y = 3/5x +4/5 slope intercept form

Step-by-step explanation:

Since we have a point and a slope, we can use the point slope form of the equation

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y--1 = 3/5(x--3)

y+1 = 3/5(x+3)  (point slope form)

We can distribute

y+1 = 3/5x +9/5

Subtract 1 from each side

y+1-1 = 3/5x +9/5 -1

y = 3/5x +9/5 -5/5

y = 3/5x +4/5 slope intercept form

Equation:  y = 3/5 x + 4/5

Step-by-step explanation:

y = mx + b

so

b = y - mx

passes through (-3,-1) and has a slope of 3/5

So

b = -1 - (3/5) (-3)

b = -1 + 9/5

b = - 5/5 + 9/5

b = 4/5

So equation

y = 3/5 x + 4/5

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.

i need more details sorry

step-by-step explanation: