The heights of the trees in a forest are normally distributed, with a mean of 25 meters and a standard deviation of 6 meters. what is the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters? use the portion of the standard normal table given to answer the question.

z. probability
0.00. 0.5000
0.50. 0.6915
1.00. 0.8413
2.00. 0.9772
3.00. 0.9987

0.13%
0.26%
2.3%
4.6%

2.3%

Step-by-step explanation:

The formula to convert x into z distribution is

Where z is the test statistic

x is what we are looking for (in this case 37)

is the mean (in this case, it is 25)

is the standard deviation (we have 6)

Plugging these into the formula, we get:

Thus we can say we want

Note:

The table given is for any  z where

Thus, now we have:

0.0228 into percentage is 0.0228 * 100 = 2.28%

Rounded, we get 2.3%

Third answer choice is right.

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8