Trig problem number 34.
10cosx+8sqrt2=8cos+7sqrt2

10 cos x +8sqrt2 = 8cos x +7 sqrt2   collect like times together to have

10cosx-8cosx = 8√2 - 7√2 then solve to have

2cosx = √2    divide by two in both sides

cosx=√2/2     but 2= √2 *√2

so cosx= √2/(√2 * √2)   so cos x =1/√2  but we know that cos inverse of 1/√2= 45   thus cos 45 = 1/√2 thus x = 45

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v