Jim had 92 more marbles than sam. after sam gave jim 18 marbles, jim had twice as many marbles as sam. how many marbles did jim have at first?

238

Step-by-step explanation:

let the number of marbles Sam has be x, then

Jim has x + 92 ← 92 more than Sam

After swap of 18 marbles

Sam has x - 18 and sam has x + 92 + 18 = x + 110

Jim now has twice as many as Sam, that is

x + 110 = 2(x - 18)

x + 110 = 2x - 36 ( subtract x from both sides )

110 = x - 36 ( add 36 to both sides )

146 = x

At first Jim had 146 + 92 = 238 marbles

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: