If a = 11 ft, b = 5 ft, and c = 7 ft, what is the surface area of the geometric shape formed by this net?
a. 167 sq. ft.
b. 145 sq. ft.
c. 117.5 sq. ft.
d. 147 sq. ft.

the answer is B.  145 sq. ft.

Step-by-step explanation:

find the area of the first 2 triangles

A = 1/2 bh

A = 1/2 ba

a = 1/2 (11 ft.) (5 ft)

a =  27.5 sq ft.

A = 1/2 cb

a = 1/2 (5 ft) (7 ft)

a = 17.5 sq. ft

find the area of the rectangle

A = lw

a = (11 ft.)(5 ft.)

a = 55 sq. ft

Then add all together

2(27.5 sq.ft) + 2(17.5 sq. ft) + 55 sq.ft. = 145 sq. ft.

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step-by-step explanation:

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts