The figure below is a net for a triangular prism. side a = 45 inches, side b = 14 inches, side c = 30 inches, and altitude d = 20 inches. what is the surface area of this figure?

a. 2,370 square inches
b. 1,950 square inches
c. 3,000 square inches
d. 2,790 square inches

the answer is A.  2370 sq. in

Step-by-step explanation:

area of the triangles first

A = 1/2 ad

a = (45 in) (20 in)

a = 1/2 (900 sq in)

a = 450 sq in

***remember to multiply 450 * 2 because you have 2 triangles***

Total area of both triangles is 900 sq. in.

Find the area of the 3 rectangles A = LW

1st rectangle and 2nd rectangle

a = cb

a = (30 in) (14 in)

a = 420 sq in. (make sure you add this again in the Total Surface area)

3rd rectangle

a = ab

a = (45 in) (14 in)

a = 630 sq. in

Total Surface area = 2 (1/2 ad) + 2(cb) + (ab)

= 2 (450 sq. in) + 2 (420 sq. in) + 630 sq. in

= 900 sq. in + 840 sq. in + 630 sq. in

= 2370 sq. in

not solvable

step-by-step explanation:

we need more information, or at least an

answer: i think it is (1,-2)