Line ab passes through a(-3, 0) and b(-6, 5). what is the equation of the line that passes through the origin and is parallel to ?
a.
5x − 3y = 0
b.
-x + 3y = 0
c.
-5x − 3y = 0
d.
3x + 5y = 0
e.
-3x + 5y = 0

3y+5x=0

Step-by-step explanation:

The question is on equations of parallel lines

Finding the gradient m of line AB

m=change in y coordinates/change in x-co-ordinates

Given points A(-3,0) and B (-6,5)

m=Δy/Δx  Δy=5-0=5      Δx=-6 - -3= -3  ⇒m= - 5/3

Equation

The line will have its gradient equal to - 5/3

m=-5/3  

point is the origin (0,0)

m=Δy/Δx

y-0/x-0 = -5/3

3(y-0)=-5(x-0)

3y-0= -5x+0

3y=-5x

3y+5x=0

where is the image?

step-by-step explanation:

step-by-step explanation: