Which is a solution for the equation log (2x-1) + log 5=1

Step-by-step explanation:

When we don't have any base with "log", we assume it to have base 10.

Using the property Log M + Log N = Log(M*N), we can write:

Log (2x-1) + Log 5 = 1

Log ((2x-1)(5)) = 1

We can turn this into exponential form using  

Thus,

step-by-step explanation:

i think you should think about the question and not look online.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?